## FANDOM

16 Pages

The article will discuss the probability of obtaining two heads in a row in n tosses with heads and tails having different probablilities.

## Derivation Edit

to come soon...

$P(n) = P(n-1) + (1-P(n-1))P(H) - (1-P(n-2) )P(H)P(T)$

  where P(H) is the probability of heads and P(T) is the probability of tails.


Thus:

$P(n) = P(n-1) + (1-P(n-1))P(H) - (1-P(n-2) )P(H)(1-P(H))$