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The article will discuss the probability of obtaining two heads in a row in n tosses with heads and tails having different probablilities.



Derivation Edit

to come soon...

$ P(n) = P(n-1) + (1-P(n-1))P(H) - (1-P(n-2) )P(H)P(T) $

  where P(H) is the probability of heads and P(T) is the probability of tails.

Thus:

$ P(n) = P(n-1) + (1-P(n-1))P(H) - (1-P(n-2) )P(H)(1-P(H)) $